Optimal. Leaf size=61 \[ -\frac{(f+g x)^2 \left (a^2+2 a b x+b^2 x^2\right )^p (a c+b c x)^{-2 p}}{2 c^3 (a+b x)^2 (b f-a g)} \]
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Rubi [A] time = 0.121584, antiderivative size = 61, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 38, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.079 \[ -\frac{(f+g x)^2 \left (a^2+2 a b x+b^2 x^2\right )^p (a c+b c x)^{-2 p}}{2 c^3 (a+b x)^2 (b f-a g)} \]
Antiderivative was successfully verified.
[In] Int[(a*c + b*c*x)^(-3 - 2*p)*(f + g*x)*(a^2 + 2*a*b*x + b^2*x^2)^p,x]
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Rubi in Sympy [A] time = 41.4939, size = 88, normalized size = 1.44 \[ \frac{\left (a c + b c x\right )^{- 2 p - 2} \left (a g - b f\right ) \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{p}}{2 b^{2} c} - \frac{g \left (a c + b c x\right )^{- 2 p - 1} \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{p}}{b^{2} c^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((b*c*x+a*c)**(-3-2*p)*(g*x+f)*(b**2*x**2+2*a*b*x+a**2)**p,x)
[Out]
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Mathematica [A] time = 0.060496, size = 49, normalized size = 0.8 \[ -\frac{\left ((a+b x)^2\right )^p (c (a+b x))^{-2 p} (a g+b (f+2 g x))}{2 b^2 c^3 (a+b x)^2} \]
Antiderivative was successfully verified.
[In] Integrate[(a*c + b*c*x)^(-3 - 2*p)*(f + g*x)*(a^2 + 2*a*b*x + b^2*x^2)^p,x]
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Maple [A] time = 0.008, size = 55, normalized size = 0.9 \[ -{\frac{ \left ( bx+a \right ) \left ( 2\,bgx+ag+bf \right ) \left ( bxc+ac \right ) ^{-3-2\,p} \left ({b}^{2}{x}^{2}+2\,abx+{a}^{2} \right ) ^{p}}{2\,{b}^{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((b*c*x+a*c)^(-3-2*p)*(g*x+f)*(b^2*x^2+2*a*b*x+a^2)^p,x)
[Out]
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Maxima [A] time = 0.725432, size = 136, normalized size = 2.23 \[ -\frac{{\left (2 \, b x + a\right )} g}{2 \,{\left (b^{4} c^{2 \, p + 3} x^{2} + 2 \, a b^{3} c^{2 \, p + 3} x + a^{2} b^{2} c^{2 \, p + 3}\right )}} - \frac{f}{2 \,{\left (b^{3} c^{2 \, p + 3} x^{2} + 2 \, a b^{2} c^{2 \, p + 3} x + a^{2} b c^{2 \, p + 3}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((g*x + f)*(b^2*x^2 + 2*a*b*x + a^2)^p*(b*c*x + a*c)^(-2*p - 3),x, algorithm="maxima")
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Fricas [A] time = 0.299543, size = 70, normalized size = 1.15 \[ -\frac{{\left (2 \, b g x + b f + a g\right )} \frac{1}{c^{2}}^{p}}{2 \,{\left (b^{4} c^{3} x^{2} + 2 \, a b^{3} c^{3} x + a^{2} b^{2} c^{3}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((g*x + f)*(b^2*x^2 + 2*a*b*x + a^2)^p*(b*c*x + a*c)^(-2*p - 3),x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*c*x+a*c)**(-3-2*p)*(g*x+f)*(b**2*x**2+2*a*b*x+a**2)**p,x)
[Out]
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GIAC/XCAS [A] time = 0.29225, size = 177, normalized size = 2.9 \[ -\frac{2 \, b^{2} g x^{2} e^{\left (-2 \, p{\rm ln}\left (c\right ) - 3 \,{\rm ln}\left (b x + a\right ) - 3 \,{\rm ln}\left (c\right )\right )} + b^{2} f x e^{\left (-2 \, p{\rm ln}\left (c\right ) - 3 \,{\rm ln}\left (b x + a\right ) - 3 \,{\rm ln}\left (c\right )\right )} + 3 \, a b g x e^{\left (-2 \, p{\rm ln}\left (c\right ) - 3 \,{\rm ln}\left (b x + a\right ) - 3 \,{\rm ln}\left (c\right )\right )} + a b f e^{\left (-2 \, p{\rm ln}\left (c\right ) - 3 \,{\rm ln}\left (b x + a\right ) - 3 \,{\rm ln}\left (c\right )\right )} + a^{2} g e^{\left (-2 \, p{\rm ln}\left (c\right ) - 3 \,{\rm ln}\left (b x + a\right ) - 3 \,{\rm ln}\left (c\right )\right )}}{2 \, b^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((g*x + f)*(b^2*x^2 + 2*a*b*x + a^2)^p*(b*c*x + a*c)^(-2*p - 3),x, algorithm="giac")
[Out]